$m^{4}-1=(m^{2}+1)(m^{2}-1)$

$2x^{2}-7x+10=2(x^{2}-3.5x+5)$

$x^{3}-9x=$

$x^{2}-12x+32=$

$100-a^{4}=(10-a^{2})(10+a^{2})$

$25x^{3}-15x^{2}-15=5(5x^{3}-3x^{2}-3)$

$x^{2}-14x+49=(x-7)^{2}$

$(x+5)^{2}-49=x^{2}+10x+25-49=x^{2}+10x-24$