$2 \times 3^2 - (2^2 + 2) = 2 \times \_\_\_ (\_\_\_ + 2) = \_\_\_ - \_\_\_ =$

$\frac{10 \div (8 - 6) + 9 \times 4}{3^2 + 3^5} = \frac{10 \div \_\_\_ + 9 \times 4}{\_\_\_ + \_\_\_} = \frac{\_\_\_ + \_\_\_}{\_\_\_} =$